jQuery array (type thing)

[sarahA]

I want to collect a series of IDs on a page and then push them through to a PHP script as a comma separated list. In a nutshell

for each row
save the userID into an array
implode/join the array values by a comma
send to php script

I have

Code:

var userids = $();
$('tr.am').each(function(i,row){
var rowid = $(row).attr('id');
var row_id = rowid.split('_');
userids = userids.add( row_id[3] );
});

// need to join userids to get 1,2,3,4,5 etc.

$.getJSON("includes/script.inc.php", {uid: userids, y: yr, m: mth}, function(data) {
etc.

With an array I would use userids.join(','); but this isn't an array as such but using the jQuery object (I found this idea/method whilst looking for something else and read it was better to use than creating an Array).

Anyone got an idea how I can take userids and get them into a comma separated values string?

TIA

[Whatever]

Isn't this was what you were helping me with Sarah on my 'basic form' thread.

The form I was submitting wanted to use a comma separated values string too.

[sarahA]

yes, I can do it in PHP, but I don't know how in jQuery as it's not an array it's an object.

Currently found a way to turn the object back to an array, not sure if that's the best solution but it's the easiest one at present.

[JasonD]

If you don't need anything special with $() then don't use it.

var userids = [];
...
userids.push(row_id[3]);
...
userids = userids.toString();

[sarahA]

Thanks Jason. No I'm not doing anything special, just collecting IDs and then creating a CSV list out of them, I just read it was the better way to do it 

Daft question but I presume the userids will go into the function no problem (i.e. unlike PHP where you'd have to pass it in or make it global). Sorry, I don't use JS much these days and am quite out of touch!

[sarahA]

Okay, got that bit working, thank you Jason.

Kind of following on from my daft question above, but not so daft as needed now...

If I set a variable within the each() loop, how do I access it outside of the function?

[samhs]

You need to define it outside the function to make it global, then set the value inside the function. With an each() iteration, you don't get to return a value, so that's the only practical way to do it AFAIK

[sarahA]

Cheers Sam. Makes sense Will give that a play with tomorrow.